X^2+10x+124=180

Solution for X^2+10x+124=180 equation:

X^2+10X+124=180

We move all terms to the left:

X^2+10X+124-(180)=0

We add all the numbers together, and all the variables

X^2+10X-56=0

a = 1; b = 10; c = -56;
Δ = b2-4ac
Δ = 102-4·1·(-56)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-18}{2*1}=\frac{-28}{2}
=-14
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+18}{2*1}=\frac{8}{2}
=4
$